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Answer :
Final answer:
The velocity of the tennis ball just before it strikes the floor is calculated using the kinematic equation v = \( \sqrt{2gh} \), resulting in approximately 5.42 m/s.
Explanation:
To find the velocity of the tennis ball just before it strikes the floor, we will use the kinematic equation for an object under constant gravitational acceleration without initial velocity:
v = \( \sqrt{2gh} \)
Here, g is the acceleration due to gravity (approximately 9.81 m/s2) and h is the height of 1.50 m. Plugging in the values:
v = \( \sqrt{2 \times 9.81 \times 1.50} \) ≈ \( \sqrt{29.43} \)
Therefore, the velocity just before impact is approximately 5.42 m/s.
Velocity is the prime indicator of the position as well as the rapidity of the object. It can be defined as the distance covered by an object in unit time. Velocity can be defined as the displacement of the object in unit time.
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