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Answer :
Final answer:
To calculate the molarity of a 6.00 g KOH solution in 5.0 L, convert the mass to moles using the molar mass of KOH and then divide by the volume in liters, resulting in a molarity of 0.02138 M.
Explanation:
The molarity of a KOH solution with 6.00 g of KOH in 5.0 L of solution can be calculated by first determining the number of moles of KOH and then dividing by the volume of the solution in liters.
First, find the molar mass of KOH by adding the atomic masses of potassium (K), oxygen (O), and hydrogen (H): Molar mass of KOH = 39.10 + 16.00 + 1.01 = 56.11 g/mol. Next, convert the mass of KOH to moles: Number of moles = Mass of KOH (g) / Molar mass of KOH (g/mol) = 6.00 g / 56.11 g/mol = 0.1069 mol. Then calculate the molarity: Molarity = Moles of solute / Volume of solution (L) = 0.1069 mol / 5.0 L = 0.02138 mol/L.
Therefore, the molarity of the KOH solution is 0.02138 M.
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