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Answer :
To solve the problem involving the cylindrical barrel, let's break it down into the required parts.
1.1. Determine the radius of a barrel (drum) in centimetres.
The diameter of the barrel is given as 18 inches. To find the radius:
Convert the diameter from inches to centimetres:
[tex]18 \text{ inches} \times 2.54 \text{ cm/inch} = 45.72 \text{ cm}[/tex]
Calculate the radius, which is half of the diameter:
[tex]\text{Radius} = \frac{45.72 \text{ cm}}{2} = 22.86 \text{ cm}[/tex]
1.2. Show, by calculations, that the height of the barrel is 96.82 cm.
We're provided with the volume of the barrel in gallons. First, convert this volume to cubic centimeters:
Convert volume from gallons to litres:
[tex]42 \text{ gallons} \times 3.78541 \text{ L/gallon} = 158.94922 \text{ L}[/tex]
Convert litres to cubic centimeters (since 1 L = 1000 cm³):
[tex]158.94922 \text{ L} \times 1000 \text{ cm}^3/\text{L} = 158949.22 \text{ cm}^3[/tex]
Calculate the height of the cylinder using the formula for the volume of a cylinder [tex]V = \pi \times r^2 \times h[/tex]:
[tex]158949.22 = 3.142 \times (22.86)^2 \times h[/tex]
Solve for [tex]h[/tex]:
[tex]h = \frac{158949.22}{3.142 \times 522.9796} \approx 96.82 \text{ cm}[/tex]
1.3. Calculate the surface area of this barrel in m².
Using the surface area formula for a closed cylinder, [tex]A = 2\pi r^2 + 2\pi rh[/tex]:
Calculate the surface area in cm²:
[tex]A = 2 \times 3.142 \times (22.86)^2 + 2 \times 3.142 \times 22.86 \times 96.82[/tex]
Evaluate the components:
- [tex]2 \times 3.142 \times (22.86)^2 = 3281.476[/tex]
- [tex]2 \times 3.142 \times 22.86 \times 96.82 = 13919.0848[/tex]
Total surface area in cm²:
[tex]3281.476 + 13919.0848 = 17200.5608 \text{ cm}^2[/tex]
Convert cm² to m² (since 1 m² = 10,000 cm²):
[tex]\frac{17200.5608}{10000} = 1.72005608 \text{ m}^2[/tex]
Thus, the surface area of the barrel is approximately [tex]1.72 \text{ m}^2[/tex].
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