We appreciate your visit to Based on the information in the table what is tex Delta H circ tex for the reaction tex SO 2 g frac 1 2 O. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To find [tex]\(\Delta H^{\circ}\)[/tex] for the reaction [tex]\(SO_2(g) + \frac{1}{2} O_2(g) \rightarrow SO_3(g)\)[/tex], we can use the standard enthalpies of formation ([tex]\(\Delta H_f^{\circ}\)[/tex]) for each substance involved.
Here's how we can calculate it step-by-step:
1. Recall the formula for [tex]\(\Delta H^{\circ}\)[/tex]:
[tex]\[
\Delta H^{\circ} = \sum \Delta H_f^{\circ} (\text{products}) - \sum \Delta H_f^{\circ} (\text{reactants})
\][/tex]
2. Identify the standard enthalpies of formation ([tex]\(\Delta H_f^{\circ}\)[/tex]) from the table:
- For [tex]\(SO_3(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = -395.2 \, \text{kJ/mol}\)[/tex]
- For [tex]\(SO_2(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = -296.1 \, \text{kJ/mol}\)[/tex]
- For [tex]\(O_2(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = 0.0 \, \text{kJ/mol}\)[/tex] (since it's an element in its standard state)
3. Plug these values into the formula:
The products side of the reaction is [tex]\(SO_3(g)\)[/tex], and the reactants side is [tex]\(SO_2(g) + \frac{1}{2} O_2(g)\)[/tex].
[tex]\[
\Delta H^{\circ} = \left[ \Delta H_f^{\circ} (\text{SO}_3) \right] - \left[ \Delta H_f^{\circ} (\text{SO}_2) + \frac{1}{2} \Delta H_f^{\circ} (\text{O}_2) \right]
\][/tex]
[tex]\[
\Delta H^{\circ} = \left[ -395.2 \right] - \left[ -296.1 + 0.5 \times 0.0 \right]
\][/tex]
4. Calculate the [tex]\(\Delta H^{\circ}\)[/tex]:
[tex]\[
\Delta H^{\circ} = -395.2 - (-296.1)
\][/tex]
[tex]\[
\Delta H^{\circ} = -395.2 + 296.1
\][/tex]
[tex]\[
\Delta H^{\circ} = -99.1 \, \text{kJ/mol}
\][/tex]
Based on the calculations, the change in enthalpy for the reaction is [tex]\(-99.1 \, \text{kJ/mol}_{\text{rxn}}\)[/tex].
So, the correct answer is (B) [tex]\(-99.1 \, \text{kJ/mol}_{\text{rxn}}\)[/tex].
Here's how we can calculate it step-by-step:
1. Recall the formula for [tex]\(\Delta H^{\circ}\)[/tex]:
[tex]\[
\Delta H^{\circ} = \sum \Delta H_f^{\circ} (\text{products}) - \sum \Delta H_f^{\circ} (\text{reactants})
\][/tex]
2. Identify the standard enthalpies of formation ([tex]\(\Delta H_f^{\circ}\)[/tex]) from the table:
- For [tex]\(SO_3(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = -395.2 \, \text{kJ/mol}\)[/tex]
- For [tex]\(SO_2(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = -296.1 \, \text{kJ/mol}\)[/tex]
- For [tex]\(O_2(g)\)[/tex], [tex]\(\Delta H_f^{\circ} = 0.0 \, \text{kJ/mol}\)[/tex] (since it's an element in its standard state)
3. Plug these values into the formula:
The products side of the reaction is [tex]\(SO_3(g)\)[/tex], and the reactants side is [tex]\(SO_2(g) + \frac{1}{2} O_2(g)\)[/tex].
[tex]\[
\Delta H^{\circ} = \left[ \Delta H_f^{\circ} (\text{SO}_3) \right] - \left[ \Delta H_f^{\circ} (\text{SO}_2) + \frac{1}{2} \Delta H_f^{\circ} (\text{O}_2) \right]
\][/tex]
[tex]\[
\Delta H^{\circ} = \left[ -395.2 \right] - \left[ -296.1 + 0.5 \times 0.0 \right]
\][/tex]
4. Calculate the [tex]\(\Delta H^{\circ}\)[/tex]:
[tex]\[
\Delta H^{\circ} = -395.2 - (-296.1)
\][/tex]
[tex]\[
\Delta H^{\circ} = -395.2 + 296.1
\][/tex]
[tex]\[
\Delta H^{\circ} = -99.1 \, \text{kJ/mol}
\][/tex]
Based on the calculations, the change in enthalpy for the reaction is [tex]\(-99.1 \, \text{kJ/mol}_{\text{rxn}}\)[/tex].
So, the correct answer is (B) [tex]\(-99.1 \, \text{kJ/mol}_{\text{rxn}}\)[/tex].
Thanks for taking the time to read Based on the information in the table what is tex Delta H circ tex for the reaction tex SO 2 g frac 1 2 O. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
