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For the host address 10. 28. 94. 135 /27 the last usable host address in the subnet would be
A. 10. 28. 94. 62
B. 10. 28. 94. 94
C. 10. 28. 94. 126
D. 10. 28. 94. 158

Answer :

The last usable host address in the subnet for the address 10. 28. 94. 135 /27 is D. 10. 28. 94. 158.Therefore, the correct answer is option D. 10. 28. 94. 158.

The last usable host address in the subnet for the host address 10. 28. 94. 135 /27. Given this notation, /27 indicates that the first 27 bits are the network part of the address, leaving the last 5 bits for host addresses. This implies a subnet mask of 255.255.255.224, which defines a block size of 32 addresses (2^5). Since the subnet's first address is the network identifier and the last address is the broadcast address, these two are not usable for hosts. To calculate the range of the subnet, we use the binary representation of the last octet of the address: 135 in binary is 10000111. The last 5 bits (01111) are the host part, which reset at the subnet boundary to 00000. For the network 10.28.94.128/27, the range of host addresses is 10.28.94.129 to 10.28.94.158. Therefore, the last usable host address is one less than the broadcast (10.28.94.159), which is 10.28.94.158.

Thus, the correct answer is D. 10. 28. 94. 158.

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