Earwax type is a Mendelian human trait; specifically, wet earwax (W) is a dominant allele, and dry earwax (w) is a recessive allele. Which percentages represent a first-generation monohybrid cross between parents with WW and ww genotypes?

A. 75% WW and 25% ww
B. 50% WW, 25% Ww, and 25% ww
C. 50% WW and 50% ww
D. 100% Ww

Question

04-05-2024
Biology

High School

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Earwax type is a Mendelian human trait; specifically, wet earwax (W) is a dominant allele, and dry earwax (w) is a recessive allele. Which percentages represent a first-generation monohybrid cross between parents with WW and ww genotypes?

A. 75% WW and 25% ww
B. 50% WW, 25% Ww, and 25% ww
C. 50% WW and 50% ww
D. 100% Ww

Answer :

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JacobWilliamsJr JacobWilliamsJr · Answer 1 · 2024-01-07T13:29:39-05:00

All offspring from a monohybrid cross between parents with genotypes WW and ww will have a 100% chance of being Ww, expressing the dominant wet earwax phenotype. Therefore, the correct option is D.

The answer to the question: Which percentages represent a first-generation monohybrid cross between parents with WW and ww genotypes? is d) 100% Ww. In this scenario, one parent has the homozygous dominant genotype WW (wet earwax) and the other has the homozygous recessive genotype ww (dry earwax).

A monohybrid cross between these genotypes will result in all offspring having the heterozygous genotype Ww, carrying one allele for wet earwax and one for dry earwax. Since the wet earwax trait is dominant, all the offspring will express the wet earwax phenotype.

In terms of Punnett square, each square would represent a Ww genotype, symbolizing the allele combination from each parent. In this scenario, no other genotypes are possible. Thus, there is a 100% chance of the offspring having a Ww genotype, and accordingly, a wet earwax phenotype.