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Answer :
Final answer:
To calculate the acceleration of the elevator when the scale registers 44.3 kg, use Newton's second law to set up an equation and solve for acceleration.
Explanation:
To calculate the acceleration of the elevator when the scale registers 44.3 kg, we need to use Newton's second law. The net force acting on the person is equal to the force exerted by the scale minus the weight of the person. We can set up the equation as follows:
Fs - w = ma
Where Fs is the force exerted by the scale, w is the weight of the person, and a is the acceleration of the elevator. Plugging in the values, we have:
(44.3 kg)g - (35.9 kg)g = (44.3 kg)a
Simplifying the equation, we have:
a = ((44.3 kg)g - (35.9 kg)g) / (44.3 kg)
Using the acceleration due to gravity, g = 9.81 m/s², we can calculate the acceleration of the elevator.
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Answer and Explanation:
To solve this problem, we need to use the formula for weight, which is given by the product of mass and acceleration of gravity. The weight of an object can be calculated by multiplying its mass by the acceleration due to gravity. In this case, the weight of the person on the scale is given by the difference between the two readings on the scale, which is 44.3 kg - 35.9 kg = 8.4 kg.
Since the acceleration of gravity is known to be 9.81 m/s^2, we can use this value to calculate the acceleration of the elevator (lift) when the scale registers 44.3 kg. The formula for acceleration is given by the change in velocity over time. In this case, the change in velocity is the difference between the person's weight when the elevator is stationary and when it is accelerating upwards. This means that the acceleration of the elevator (lift) is given by 8.4 kg / (9.81 m/s^2 * t), where t is the time over which the acceleration occurs.
Therefore, to calculate the acceleration of the elevator (lift), we need to know the time over which the acceleration occurs. Since this information is not provided in the question, we cannot determine the exact acceleration of the elevator (lift). However, we can say that the acceleration of the elevator (lift) is proportional to the difference in weight readings on the scale and inversely proportional to the acceleration of gravity.
