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Answer :
To solve this problem, we need to determine the number of protons, neutrons, and electrons in the isotope of lead denoted by the symbol [tex]\({ }_{82}^{208} \text{Pb}\)[/tex].
1. Understanding the Symbol:
- The subscript number (82) is the atomic number, which tells us the number of protons in the atom. So, there are 82 protons.
- The superscript number (208) is the mass number, which is the total number of protons and neutrons in the atom.
2. Calculate the Number of Neutrons:
- To find the number of neutrons, subtract the number of protons from the mass number:
[tex]\[
\text{Neutrons} = \text{Mass number} - \text{Protons} = 208 - 82 = 126
\][/tex]
- So, there are 126 neutrons.
3. Determine the Number of Electrons:
- In a neutral atom, the number of electrons is equal to the number of protons, because the positive charges (protons) balance with the negative charges (electrons).
- Therefore, there are 82 electrons.
Based on the calculations, a neutral atom of this lead isotope has 82 protons, 126 neutrons, and 82 electrons.
1. Understanding the Symbol:
- The subscript number (82) is the atomic number, which tells us the number of protons in the atom. So, there are 82 protons.
- The superscript number (208) is the mass number, which is the total number of protons and neutrons in the atom.
2. Calculate the Number of Neutrons:
- To find the number of neutrons, subtract the number of protons from the mass number:
[tex]\[
\text{Neutrons} = \text{Mass number} - \text{Protons} = 208 - 82 = 126
\][/tex]
- So, there are 126 neutrons.
3. Determine the Number of Electrons:
- In a neutral atom, the number of electrons is equal to the number of protons, because the positive charges (protons) balance with the negative charges (electrons).
- Therefore, there are 82 electrons.
Based on the calculations, a neutral atom of this lead isotope has 82 protons, 126 neutrons, and 82 electrons.
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