Answer :

Final answer:

To find the limiting reactant between H2 and O2, mole calculations based on their molar masses must be performed. The one providing fewer moles in comparison to the stoichiometric ratio of the balanced reaction will be the limiting reactant.

Explanation:

The question is asking to identify the limiting reactant when 7.8 g of H2 reacts with 37.6 g of O2 according to the reaction 2H2 + O2
ightarrow 2H2O. To determine the limiting reactant, we calculate the moles of each reactant using their molar masses and then apply the stoichiometry of the balanced chemical equation.

The balanced equation shows that 2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O. After performing mass-to-mole conversions, we can compare the mole ratio of the reactants to the stoichiometric coefficients in the balanced equation. The reactant which does not provide enough moles to satisfy the stoichiometric ratio required for a complete reaction is the limiting reactant.

Once the limiting reactant is identified, no further reaction will occur even if the other reactant is still present, and this excess reactant will determine the maximum amount of product that can be formed. For this particular problem, the calculations must be performed to ascertain whether H2 or O2 is the limiting reactant.

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