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From her eye, which stands 1.69 m above the ground, Sadie measures the angle of elevation to the top of a prominent skyscraper to be 36°. If she is standing at a horizontal distance of 275 m from the base of the skyscraper, what is the height of the skyscraper?

Round your answer to the nearest hundredth if necessary.

Answer :

The height of the skyscraper is approximately 166.68 meters.

Sadie's position and the angle of elevation allow us to use trigonometry to find the height of the skyscraper. Using the tangent function, we have:

[tex]\[ \tan(36^\circ) = \frac{\text{height of skyscraper}}{\text{horizontal distance from Sadie to the base of the skyscraper}} \][/tex]

[tex]\[ \tan(36^\circ) = \frac{\text{height of skyscraper}}{275 \, \text{m}} \][/tex]

To find the height of the skyscraper, we rearrange the equation:

[tex]\[ \text{height of skyscraper} = 275 \, \text{m} \times \tan(36^\circ) \][/tex]

[tex]\[ \text{height of skyscraper} \approx 166.68 \, \text{m} \][/tex]

Rounding to the nearest hundredth, the height of the skyscraper is approximately 166.68 meters. Hence, the final answer is 166.68 meters.

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Rewritten by : Barada