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There is a semi-permeable membrane separating two solutions, A and B. The membrane is permeable to glucose, water, and urea, but not to anything else.

- Side A contains an aqueous solution with 0.3 M sucrose, 0.5 M glucose, and 0.1 M urea.
- Side B contains an aqueous solution with 0.7 M sucrose, 0.3 M glucose, and 0.2 M urea.

Note: Molar (M) is a measure of concentration.

Answer :

Final answer:

In a semi-permeable membrane separating two solutions, substances that can pass through the membrane, such as glucose and urea, will move from areas of higher concentration to lower until equilibrium is reached. In this case, glucose will move from Side A to Side B, and urea will move from Side B to Side A.

Explanation:

The subject of your question pertains to diffusion through a semi-permeable membrane. In this scenario, substances like glucose, water, and urea will move from an area of higher concentration to an area of lower concentration to reach equilibrium. This principle is governed by the laws of osmosis.

Since sucrose cannot pass through the membrane, it does not contribute to the osmosis. But for glucose and urea, which can, they will migrate until there is a balance. Because Side A has a higher concentration of glucose and a lower concentration of urea compared to Side B, glucose will move from Side A to Side B, and urea will move from Side B to Side A until both sides reach an equal concentration for each molecule.

Learn more about osmosis here:

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