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Answer :
Final answer:
The argon in the canister can purge approximately 0.0307 wine bottles.
Explanation:
To calculate the number of 750.0 mL wine bottles that can be purged with the argon in the canister, we can use the ideal gas law, PV = nRT.
First, we need to convert the volume of the wine bottle to liters. Since 1 L = 1000 mL, the volume of the wine bottle is 0.750 L.
Next, we can rearrange the ideal gas law to solve for the number of moles, n:
n = PV / RT
Substituting the given values:
n = (1.00 bar) * (0.750 L) / [(0.0831 L·bar/mol·K) * (291 K)]
Simplifying the equation:
n = 0.0307 mol
Since 1 mole of argon gas can purge 1 wine bottle, the number of wine bottles that can be purged with the argon in the canister is 0.0307 bottles.
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