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A current of 5 A flows through a resistor for 2 minutes and produces 3000 J of heat. What is the value of the resistance?

A. 1Ω
B. 2Ω
C. 4Ω
D. 5Ω

Answer :

Answer:

the value of the resistance is 1 Ω

Explanation:

The formula for calculating energy dissipated as heat in a resistor is:

  • E = I²RT

Where,

  • I is current
  • R is Resistance
  • T is time

we are given :

5A of current flowing through a resistor for 2 minute produced 3000 j of heat.

  • Here, Current (I) = 5A
  • Time (t) = 2 minutes = 120 seconds

Plug in the given values in the above formula

  • 3000 = 5²*R*120
  • 3000 = 25*R*120
  • 3000 = 3000R

divide both sides by 3000

  • R = 1 Ω

Hence, the value of the resistance is 1 Ω

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Rewritten by : Barada

Final answer:

Using the power and energy formulas in combination with Ohm's Law, the value of the resistance that produces 3000 J of heat when 5A of current flows through it for 2 minutes is found to be 1 Ω (ohm).

Explanation:

When 5A of current flow through a resistor for 2 minutes and produce 3000 J (joules) of heat, we use the formula for power (P = VI), and the energy (E) formula E = Pt to find the resistance. First, we calculate the power as P = E/t, where E is energy in joules, and t is time in seconds. In this case, E = 3000 J and t = 2 minutes, which is 120 seconds. So P = 3000 J / 120 s = 25 W (watts). Since P = I²R, we can solve for R, the resistance, as R = P / I². Given that I = 5 A, we find that R = 25 W / (5 A)² = 1 Ω (ohm).