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Answer :
If the vapor pressure of benzene is 100.0 mmHg at 26.1°C, the vapor pressure of the solution is 87.4 mmHg.
How to calculate vapour pressure
To calculate the vapor pressure of the solution, use Raoult's law, which says the vapor pressure of a solution is proportional to the mole fraction of the solvent in the solution:
P_solution = X_benzene * P_benzene
where
P_solution is the vapor pressure of the solution,
X_benzene is the mole fraction of benzene in the solution, and
P_benzene is the vapor pressure of pure benzene.
To find the mole fraction of benzene, calculate the moles of each component in the solution
moles of benzene = 98.2 g / 78.11 g/mol = 1.257 mol
moles of camphor = 27.6 g / 152.23 g/mol = 0.181 mol
The total moles of the solution is the sum of the moles of benzene and camphor
total moles = 1.257 mol + 0.181 mol
= 1.438 mol
The mole fraction of benzene is the moles of benzene divided by the total moles
X_benzene = 1.257 mol / 1.438 mol
= 0.874
Substituting the given values
P_solution = X_benzene * P_benzene
P_solution = 0.874 * 100.0 mmHg
P_solution = 87.4 mmHg
Therefore, the vapor pressure of the solution is 87.4 mmHg.
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