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Answer :
The current rate of change of sales is approximately 157.15 dollars per week.
To find the current rate of change of sales (ds/dx) with respect to weekly advertising costs (x), we need to take the derivative of the sales function (s) with respect to x.
Given the sales function:
s = 60000 − 350000[tex]e^{(-0.0004X)}[/tex]
Let's differentiate both sides of the equation with respect to x:
ds/dx = d/dx (60000 − 350000[tex]e^{(-0.0004X)}[/tex]
To differentiate the function, we need to apply the chain rule. The chain rule states that if we have a function g(f(x)), then its derivative with respect to x is given by g'(f(x) × f'(x).
In our case, g(u) = 60000 - 350000[tex]e^{u}[/tex], and f(x) = -0.0004x.
Now, let's find the derivatives:
g'(u) = d/du (60000 - 350000[tex]e^{u}[/tex]) = -350000e^u
f'(x) = d/dx (-0.0004x) = -0.0004
Using the chain rule, we get;
ds/dx = g'(f(x) × f'(x)
ds/dx = (-350000[tex]e^{(-0.0004X)}[/tex] × (-0.0004)
Now, we need to find the current rate of change of sales (ds/dx) when the current weekly advertising costs are $2000 (x = 2000). Additionally, the advertising costs are increasing at the rate of $300 per week, which means dx/dt = 300 (where t represents the number of weeks).
Now, we can calculate the current rate of change of sales (ds/dx) at x = 2000:
ds/dx = (-350000[tex]e^{(-0.0004X)}[/tex] × 2000) × (-0.0004)
ds/dx = (-350000[tex]e^{(-0.8)}[/tex] × (-0.0004)
To get the numerical value, let's evaluate [tex]e^{(-0.8)}[/tex]:
[tex]e^{(-0.8)}[/tex] ≈ 0.449
Now, substitute this value back into the equation:
ds/dx ≈ (-350000 × 0.449) × (-0.0004)
ds/dx ≈ 157.15
Therefore, the current rate of change of sales is approximately 157.15 dollars per week.
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