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Answer :
The energy must be added to the system to move the satellite into a circular orbit with altitude 198 km is 93.6 x 10 ^10 J
This can be calculated with the total energy concept in gravitational system. The total energy of the obital satellite will be
T.E = [tex]\frac{G*Me*m}{Re+h}[/tex]
where G - gravitational constant
Me is the mass of the earth
m is the mass of the satellite
Re is the radius of earth = 6400km
At height 108Km, the total energy is
T.E1 = GMem (1/(6400+108))
Similarly we can calculate Total energy at height 198 km
T.E2 = GMem (1/(6400+198))
So energy required would be TE1 -TE2
= GMem (1.54 x 10^-4 - 1.515 x 10^-4)
= GMem x (2.5 x 10^-6)
= 6.6 × 10^−11 x 5.972 × 10^24 x 950 x 2.5 x 10^-6
= 93,611.1 x 10 ^7
93.6 x 10 ^10
Hence the energy required would be 93.6 x 10 ^10 J .
To know more about gravitational force, visit here
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