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Answer :
The concentration of Br– when 913 mL of 0.253 M KBr is mixed with 601 mL of 0.527 M FeBr₂ is 0.374 M.
To calculate this, first calculate the total volume of the solution by adding 913 mL and 601 mL together, which is 1514 mL. Next, calculate the total moles of Br– by multiplying the molarity of KBr and its volume, 0.253 M x 913 mL, and the molarity of FeBr₂ and its volume, 0.527 M x 601 mL.
Lastly, divide the total moles of Br– by the total volume of the solution, 1514 mL, to calculate the concentration of Br–, which is 0.374 M.
To summarize, the concentration of Br– when 913 mL of 0.253 M KBr is mixed with 601 mL of 0.527 M FeBr₂ is 0.374 M. This was calculated by first finding the total volume of the solution, 1514 mL, and then calculating the total moles of Br–.
Finally, the concentration of Br– was calculated by dividing the total moles of Br– by the total volume of the solution.
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