High School

We appreciate your visit to A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second The height h after. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height \( h \) after \( t \) seconds is given by the equation:

\[ h(t) = -16t^2 + 112t + 5 \]

How many seconds until it lands?

Answer :

Final answer:

The toy rocket will land after approximately 3.79 seconds.

Explanation:

The height of the toy rocket is given by the equation h(t) = -16t^2 + 112t + 5, where h represents the height above ground level and t represents time in seconds.

To find the time until the rocket lands, we need to find the value of t when the height, h(t), is equal to 0. We can set the equation equal to 0 and solve for t.

By substituting the values into the quadratic equation, we find that the rocket lands approximately after 3.79 seconds.

Thanks for taking the time to read A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second The height h after. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada