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A 7.00 kg bowling ball is held 2.00 m above the ground. Using [tex]$g=9.80 \, \text{m/s}^2$[/tex], what potential energy does the ball have due to its position?

A. 68.6 J
B. 137 J
C. 274 J
D. 960 J

Answer :

Sure! Let's solve the problem step-by-step.

We want to find the gravitational potential energy of a bowling ball that is held at a certain height. Gravitational potential energy can be calculated using the formula:

[tex]\[ \text{Potential Energy (PE)} = m \times g \times h \][/tex]

where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (in meters per second squared), and
- [tex]\( h \)[/tex] is the height above the ground (in meters).

For our problem:
- The mass of the bowling ball, [tex]\( m \)[/tex], is 7.00 kg.
- The height, [tex]\( h \)[/tex], is 2.00 m.
- The acceleration due to gravity, [tex]\( g \)[/tex], is given as 9.80 m/s².

Now, plug these values into the formula:

[tex]\[ \text{PE} = 7.00 \, \text{kg} \times 9.80 \, \text{m/s}^2 \times 2.00 \, \text{m} \][/tex]

[tex]\[ \text{PE} = 137.2 \, \text{J} \][/tex]

So, the gravitational potential energy of the bowling ball due to its position is 137 J.

Therefore, the correct answer is 137 J.

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