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Answer :
Final answer:
By applying the law of conservation of momentum in this frictionless system, the velocity of the second bumper car after the collision is determined to be 2.0 m/s to the right. Therefore, the correct option is D.
Explanation:
This question revolves around the principle of Conservation of Momentum. In a closed system with no external forces acting (such as a frictionless surface), the total momentum of the system before a collision is equal to the total momentum after the collision.
Before the collision, the total momentum was (135 kg * 2.0 m/s) - (135 kg * 1.5 m/s) = 67.5 kg*m/s.
After the collision, the momentum of the first car is - (135 kg * 1.5 m/s) = - 202.5 kg*m/s.
To conserve momentum, the momentum of the second car must be 67.5 kg*m/s + 202.5 kg*m/s = 270 kg*m/s. Therefore, the velocity of the second car is the momentum divided by its mass, 270 kg*m/s / 135 kg = 2.0 m/s to the right. Therefore, the correct answer is D. 2.0 m/s to the right.
Learn more about Conservation of Momentum here:
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