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Answer :
Final answer:
The final position (x1) of the object is 135.0 m.
Explanation:
To find the final position (x1), we need to use the equations of kinematics and consider the work done by the drag force.
Given:
First, let's find the acceleration (a) using the equation:
F = ma
Substituting the values:
-0.200 N = 2.00 kg * a
Solving for a:
a = -0.200 N / 2.00 kg
a = -0.100 m/s^2
Next, let's find the time (t) using the equation:
v1 = v0 + at
Substituting the values:
3.00 m/s = 5.00 m/s + (-0.100 m/s^2) * t
Simplifying the equation:
-2.00 m/s = -0.100 m/s^2 * t
Solving for t:
t = (-2.00 m/s) / (-0.100 m/s^2)
t = 20.0 s
Now, let's find the displacement (s) using the equation:
s = ut + 0.5at^2
Substituting the values:
s = (5.00 m/s) * (20.0 s) + 0.5 * (-0.100 m/s^2) * (20.0 s)^2
Simplifying the equation:
s = 100.0 m - 20.0 m
s = 80.0 m
Finally, let's find the final position (x1) using the equation:
x1 = x0 + s
Substituting the values:
x1 = 55.0 m + 80.0 m
x1 = 135.0 m
Learn more about kinematics here:
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