High School

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A student is asked to solve the equation [tex]3v + 16 = 60[/tex] for [tex]v[/tex]. Their work is shown:

[tex]\[

\begin{array}{|l|l|}

\hline

\text{Original Problem} & 3v + 16 = 60 \\

\hline

\text{Step One} & \frac{3v}{3} + 16 = \frac{60}{3} \\

\hline

\text{Step Two} & v + 16 = 20 \\

\hline

\text{Step Three} & -16 - 16 \\

\hline

\text{Step Four} & v = 4 \\

\hline

\end{array}

\][/tex]

The student made a mistake in Step One. What operation should the student have performed?

A. Added 3 to both sides
B. Divided by 16 on both sides
C. Multiplied by 3 on both sides
D. Subtracted 16 on both sides

Answer :

To solve the equation [tex]\(3v + 16 = 60\)[/tex] for [tex]\(v\)[/tex], we need to isolate [tex]\(v\)[/tex] on one side of the equation. Let’s go through the steps carefully:

1. Original Equation:
The equation we start with is:
[tex]\[ 3v + 16 = 60 \][/tex]

2. Correct Operation:
In Step One, the student needs to remove the constant term (16) from the left side to begin isolating [tex]\(v\)[/tex]. To do this, the correct operation is to subtract 16 from both sides of the equation. This ensures we maintain the equality.

[tex]\[
3v + 16 - 16 = 60 - 16
\][/tex]

3. Simplifying:
Simplifying both sides gives:
[tex]\[
3v = 44
\][/tex]

4. Solving for [tex]\(v\)[/tex]:
Now that we have [tex]\(3v = 44\)[/tex], to solve for [tex]\(v\)[/tex], divide both sides by 3:

[tex]\[
v = \frac{44}{3}
\][/tex]

5. Final Answer:
The value of [tex]\(v\)[/tex] is:
[tex]\[
v = \frac{44}{3} \approx 14.67
\][/tex]

So, the correct operation that should have been performed in Step One is to subtract 16 from both sides. This process helps to systematically solve for [tex]\(v\)[/tex].

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Rewritten by : Barada