We appreciate your visit to What is the magnitude of the magnetic field inside a 372 turn toroid carrying a current of 1 69 A at a radius of 4. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The magnitude of the magnetic field inside the toroid is 0.021 Tesla. Magnitude of the magnetic field inside a toroid can be calculated using the formula: B = (μ₀ * N * I) / (2π * r)
- B represents the magnitude of the magnetic field
- μ₀ is the permeability of free space, which is a constant equal to 4π * 10⁻⁷ T*m/A
- N is the number of turns in the toroid (372 turns in this case)
- I is the current flowing through the toroid (1.69 A in this case)
- r is the radius of the toroid (4.60 m in this case)
Substituting the given values into the formula:
B = (4π * 10⁻⁷ T*m/A * 372 turns * 1.69 A) / (2π * 4.60 m)
Simplifying the expression:
B = (4 * 3.14 * 10⁻⁷ * 372 * 1.69) / (2 * 4.60)
B = 0.021 T
Therefore, the magnitude of the magnetic field inside the toroid is 0.021 Tesla.
To know more about magnetic field, refer
https://brainly.com/question/14411049
#SPJ11
Thanks for taking the time to read What is the magnitude of the magnetic field inside a 372 turn toroid carrying a current of 1 69 A at a radius of 4. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada