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A 50.0 mL sample of an unknown HCl solution was titrated with 0.449 M NaOH. To reach the equivalence point, 38.4 mL of the NaOH was used. What was the concentration of the HCl?

Answer :

The concentration of the HCl solution is determined by calculating the moles of NaOH used and leveraging the 1:1 reaction stoichiometry between HCl and NaOH. The molarity of HCl is found to be 0.345024 M.

To calculate the concentration of the HCl solution in a titration analysis, you must use the provided volume and molarity of the NaOH solution and the volume of HCl solution used. First, calculate the moles of NaOH that were required to reach the equivalence point:

Moles of NaOH = Volume of NaOH x Molarity of NaOH = 0.0384 L x 0.449 M = 0.0172512 moles

Because the reaction between HCl and NaOH is 1:1, the moles of HCl will also be 0.0172512. The molarity (concentration) of HCl is then calculated by dividing the moles of HCl by its volume in liters:

Molarity of HCl = Moles of HCl / Volume of HCl (L) = 0.0172512 moles / 0.050 L = 0.345024 M

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