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A pump flows 100 gal/min of water. The inlet pressure is 0 psig, and the outlet pressure is 20 psig.

1. What is the required shaft power (hp) of the motor, assuming the pump is 60% efficient?
2. If the motor is 85% efficient, how much electricity (kW) is required to power the motor?

Answer :

Final answer:

To calculate the required shaft power of the motor, use the equation: Power (in hp) = (Flow rate * Pressure difference) / (Efficiency). Given the provided values, the required power is 2000 gal*psig/min. To convert the power to kilowatts (kW), use the conversion factor of 1 hp = 0.7355 kW, resulting in 1471 kW.

Explanation:

To calculate the required shaft power of the motor, we can use the equation:

Power (in hp) = (Flow rate * Pressure difference) / (Efficiency)

Given that the flow rate is 100 gal/min, the pressure difference is 20 psig - 0 psig = 20 psig, and the efficiency of the pump is 60%, we can substitute these values into the equation:

Power (in hp) = (100 gal/min * 20 psig) / 60% = 2000 gal*psig/min

To convert the power to kilowatts (kW), we can use the conversion factor of 1 hp = 0.7355 kW:

Power (in kW) = 2000 gal*psig/min * 0.7355 kW/hp = 1471 kW

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