Answer :

The concentration of hydroxide ion (-OH) in 1.37 x10^-5 m solution of Ba(OH)2 is calculated as follows

write the equation for dissociation of Ba(OH)2

Ba(OH)2 = Ba^2+(aq) + 2OH^-(aq)

by use of mole ratio between Ba(OH)2 to OH^- which is 1:2 the concentration of OH^- = 2x ( 1.37 x10^-5) = 2.74 x10^-5 M

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