We appreciate your visit to A 200 kg load is hung on a wire with the following properties Length 4 00 m Cross sectional area tex 0 200 times 10. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The increase in length of the wire, caused by a hanging load and calculated using the concepts of stress, strain and Young's modulus, is found to be 0.49 mm.
Explanation:
This problem deals with the concept of elastic deformation in Physics. The increase in length, referred to as strain, can be found using Hooke's Law formula: Strain = Stress / Young's modulus. In this case, the stress is the force divided by the cross-sectional area, i.e., (mass * gravity) / area. For a 200 kg mass, the force due to gravity is 200 * 9.8 = 1960 N. This gives us the stress as 1960 / 0.200 X 10⁻⁴ = 9.8 X 10⁶ N/m². Now, you can find the strain by dividing the stress by Young's modulus: 9.8 X 10⁶ / 8.00 X 10¹⁰ = 1.225 X 10⁻⁴. Finally, multiply the strain by the original length of the wire to get the increase in length which is 4.00 * 1.225 X 10⁻⁴ = 0.00049 m or 0.49 mm.
Learn more about Elastic Deformation here:
https://brainly.com/question/31577326
#SPJ11
Thanks for taking the time to read A 200 kg load is hung on a wire with the following properties Length 4 00 m Cross sectional area tex 0 200 times 10. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
