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Answer :
Final answer:
The kinetic friction that is opposing the motion of the box is 50 N to the left. This is determined by Newton's first law stating that an object in motion stays in motion at a constant velocity unless acted upon by an external force, therefore, the applied force and frictional force must be equal and opposite.
Explanation:
The kinetic friction can be calculated using Newton's first law. It states that an object in motion stays in motion with the same speed and in the same direction unless otherwise acted upon by an unbalanced force. In this case, the box is moving at a constant velocity, which means that the net force acting on it is zero. Therefore, the force being applied to the box (50N to the right) must be equal and opposite to the force of friction (meaning the frictional force is 50N to the left).
So, the kinetic friction that opposes the box's motion is 50 N to the left (Option D). This is because the forces balance each other out for the box to maintain its constant velocity.
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Final answer:
When moving at a constant velocity, the total force on an object is zero because the forces are balanced. Hence, if the student pushes the box with a 50N force to the right, the kinetic friction countering this force is also 50N, but to the left. Thus, the answer is (D) 50N left.
Explanation:
In physics, the concept of friction is very important when it comes to understanding motion. In your question, we are asked to find out the kinetic friction between a 25kg box and the floor if the student pushes it to the right with a force of 50N, and the box is moving at a constant velocity.
According to Newton's first law, if an object is moving at a constant velocity (meaning, it's not accelerating or decelerating), the total force acting on it is zero. This is due to the forces being balanced. Specifically, the force exerted to push the box is counteracted by the frictional force. So, if the student exerts a force of 50N to the right, there must be an equal force of 50N acting in the opposite direction.
Therefore, the kinetic friction in this case, is 50N to the left.
The answer is (D) 50N left.
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