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What is the density, in kg/mL, of an unknown sample of metal that has a mass of 98.3 g and occupies a volume of 1.53 mL? Be sure to report your answer with the correct number of significant figures.

Answer :

Final answer:

The density of the unknown metal sample is 64.183 kg/mL.

Explanation:

To calculate the density of the metal sample, we need to convert the given mass from grams to kilograms and the given volume from milliliters to liters.

Given:

  • Mass = 98.3 g
  • Volume = 1.53 mL

Converting the mass to kilograms:

  • Mass = 98.3 g * (1 kg / 1000 g) = 0.0983 kg

Converting the volume to liters:

  • Volume = 1.53 mL * (1 L / 1000 mL) = 0.00153 L

Now, we can calculate the density:

  • Density = Mass / Volume = 0.0983 kg / 0.00153 L = 64.183 kg/L

Since the question asks for the density in kg/mL, we need to convert the density from kg/L to kg/mL:

  • Density = 64.183 kg/L * (1 mL / 1 L) = 64.183 kg/mL

Learn more about calculating density of a metal sample here:

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