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Answer :
Final answer:
To determine the molar mass of the unknown gas that effuses 1.73 times faster than Kr, we can use Graham's law of effusion. The molar mass of the unknown gas is approximately 36.6 g/mol.
Explanation:
To determine the molar mass of the unknown gas, we can use Graham's law of effusion. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Given that the unknown gas effuses 1.73 times faster than Kr, we can set up the following equation: (Rate of unknown gas) / (Rate of Kr) = sqrt(Molar mass of Kr) / sqrt(Molar mass of unknown gas)
Plugging in the values, we get:
- (1.73) / (1) = sqrt(83.8 g/mol) / sqrt(Molar mass of unknown gas)
- Solving for the molar mass of the unknown gas, we find:
- Molar mass of unknown gas = (sqrt(83.8 g/mol))^2 / (1.73)^2
- Molar mass of unknown gas = 36.6 g/mol (approximately)
- Therefore, the correct answer is option c) 36.6 g/mol.
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