High School

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Jerald jumped from a bungee tower. If the equation that models his height, in feet, is [tex]h = -16t^2 + 729[/tex], where [tex]t[/tex] is the time in seconds, for which interval of time is he less than 104 feet above the ground?

A. [tex]t \gt 6.25[/tex]
B. [tex]-6.25 \lt t \lt 6.25[/tex]
C. [tex]t \lt 6.25[/tex]
D. [tex]0 \leq t \leq 6.25[/tex]

Answer :

Sure! Let's solve this problem step-by-step.

The equation given for Jerald's height, [tex]\( h \)[/tex], in feet, in terms of time, [tex]\( t \)[/tex], in seconds is:
[tex]\[ h = -16t^2 + 729 \][/tex]

We need to determine when Jerald's height is less than 104 feet above the ground. So, we set up the inequality:
[tex]\[ -16t^2 + 729 < 104 \][/tex]

Next, we solve this inequality step-by-step.

1. Set up the inequality:
[tex]\[ -16t^2 + 729 < 104 \][/tex]

2. Move 104 to the other side:
[tex]\[ -16t^2 + 729 - 104 < 0 \][/tex]
Simplifying, this becomes:
[tex]\[ -16t^2 + 625 < 0 \][/tex]

3. Isolate the [tex]\( t^2 \)[/tex] term:
First, subtract 625 from both sides:
[tex]\[ -16t^2 < -625 \][/tex]

Then, divide both sides by -16, and remember to reverse the inequality sign because we are dividing by a negative number:
[tex]\[ t^2 > \frac{625}{16} \][/tex]

4. Simplify:
[tex]\[ t^2 > 39.0625 \][/tex]

5. Take the square root of both sides to solve for [tex]\( t \)[/tex]:
[tex]\[ |t| > \sqrt{39.0625} \][/tex]

So,
[tex]\[ |t| > 6.25 \][/tex]

This means,
[tex]\[ t < -6.25 \quad \text{or} \quad t > 6.25 \][/tex]

But, since time [tex]\( t \)[/tex] must be positive (because it represents time elapsed since Jerald jumped):

Therefore, [tex]\( t > 6.25 \)[/tex].

So, the correct interval of time for which Jerald is less than 104 feet above the ground is:

[tex]\[ t > 6.25 \][/tex]

Thus, the answer is:
[tex]\[ t > 6.25 \][/tex]

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