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Answer :
suppose the smallest one is x, then the next one is x+2, the third one is x+4
the sum is 159, so x+(x+2)+(x+4)=159
3x+6=159
3x=153
x=51
the three odd integers are; 51, 53, 55
the sum is 159, so x+(x+2)+(x+4)=159
3x+6=159
3x=153
x=51
the three odd integers are; 51, 53, 55
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