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In the following reaction, how many liters of [tex]O_2[/tex] will produce 43.62 liters of [tex]CO_2[/tex] at STP?

\[ C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O \]

A. 72.7 liters
B. 17.45 liters
C. 14.54 liters
D. 54.53 liters
E. 36.3 liters

Answer :

Final answer:

To determine the volume of O₂ required to produce 43.62 L of CO₂ at STP, we use the stoichiometry of the balanced equation.

Cross-multiplying and solving for x, we find that x = 218.1 L O₂. Therefore, the correct answer is (d) 54.53 liters.

Explanation:

To determine the volume of O₂ required to produce 43.62 L of CO₂ at STP, we need to use the stoichiometry of the balanced equation. From the equation, we see that 5 L of O₂ is required to react with 1 L of C₃H₈. Therefore, using this ratio, we can set up a proportion to find the volume of O₂:

(5 L O₂) / (1 L C₃H₈) = (x L O₂) / (43.62 L CO₂).

Cross-multiplying and solving for x, we find that x = 218.1 L O₂. Therefore, the correct answer is (d) 54.53 liters.

Learn more about stoichiometry here:

https://brainly.com/question/34828728

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