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Answer :
Final answer:
Using Boyle's Law, which establishes the inverse relationship between pressure and volume for a gas, we calculate that the new volume of helium when the pressure drops from 99.8 kPa to 87.4 kPa is approximately 13.33 liters.
Explanation:
To find the new volume when the pressure drops, we can use Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship, provided temperature and number of moles remain constant. The formula for Boyle's Law is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.
In this case:
- P1 = 99.8 kPa
- V1 = 11.71 L
- P2 = 87.4 kPa
- V2 = ?
Solving for V2, we have:
V2 = P1 × V1 / P2
V2 = (99.8 kPa × 11.71 L) / 87.4 kPa
V2 = 13.33 L (rounded to two decimal places)
So, the new volume if the pressure drops to 87.4 kPa is approximately 13.33 liters.
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