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Answer :
Answer : The volume of 6.00 M HCl needed are, 361.5 ml
Solution :
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of HCl solution = 6.00 M
[tex]V_1[/tex] = volume of HCl solution = ?
[tex]M_2[/tex] = molarity of another HCl solution = 6.80 M
[tex]V_2[/tex] = volume of another HCl solution = 319 ml
Now put all the given values in the above law, we get the volume of HCl solution.
[tex](6.00M)\times V_1=(6.80M)\times (319ml)[/tex]
[tex]V_1=361.5ml[/tex]
Therefore, the volume of 6.00 M HCl needed are, 361.5 ml
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