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How many molecules of CO\(_2\) are present in 97.3 g of CO\(_2\)?

A) 1.33 x 10\(^{25}\)
B) 1.33 x 10\(^{24}\)
C) 1.34 x 10\(^{23}\)
D) 1.32 x 10\(^{25}\)

Answer :

Final answer:

To determine the number of molecules of CO2, we use Avogadro's number and the molar mass of CO2. The number of molecules in 97.3g of CO2 is 1.33 x 10^24 molecules.

Explanation:

To determine the number of molecules of CO2 present in 97.3g of CO2, we need to use Avogadro's number and the molar mass of CO2. The molar mass of CO2 is 44.01 g/mol, which means that 1 mole of CO2 contains 6.02 x 1023 molecules.



To convert grams of CO2 to moles, we use the formula:



moles = given mass / molar mass



moles = 97.3 g / 44.01 g/mol = 2.2117 mol



Finally, we can calculate the number of molecules by multiplying the moles by Avogadro's number:



number of molecules = moles x Avogadro's number



number of molecules = 2.2117 mol x 6.02 x 1023 molecules/mol



number of molecules = 1.33 x 1024 molecules

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