High School

We appreciate your visit to A five digit number divisible by 3 is to be formed using the numbers 0 1 2 3 4 and 5 without repetitions The total. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A five-digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4, and 5 without repetitions. The total number of ways this can be done is:

A. 216
B. 240
C. 600
D. 3125

Answer :

Final answer:

There are 600 possible five digit numbers using the numbers 0-5 without repetition that are divisible by 3. This is determined using permutations and the divisibility rule of 3.

Explanation:

This is a question of permutations and divisibility. A five digit number that is divisible by 3 using the numbers 0,1,2,3,4,5 without repetitions is to be formed. Given the restriction of no repetitions, the first place can have any of 5 numbers (1-5), second place 5 remaining choices (since 0 can be used), then 4, then 3, and finally 2 choices left for the last spot. So in total, that's a permutation of 5 x 5 x 4 x 3 x 2 = 600 possibilities. The divisibility rule of 3 states that a number is divisible by 3 if the sum of its digits is divisible by 3. Since numbers 0, 1, 2, 3, 4, 5 adds to 15 which is divisible by 3, all 600 possibilities would be divisible by 3. Therefore, the answer to the question is 600.

Learn more about Permutations and Divisibility here:

https://brainly.com/question/34353539

#SPJ11

Thanks for taking the time to read A five digit number divisible by 3 is to be formed using the numbers 0 1 2 3 4 and 5 without repetitions The total. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada