We appreciate your visit to The molar heat of vaporization of ethanol is 39 3 kJ mol and the boiling point of ethanol is 78 3 degrees Celsius Calculate the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The change in entropy (ΔS) for the vaporization of ethanol, calculated using the formula ΔS = ΔH/T, is approximately 111.8 J/mol*K.
Explanation:
The change in entropy (ΔS) for the vaporization of ethanol can be calculated using the formula ΔS = ΔH/T, where ΔH is the molar heat of vaporization and T is the absolute temperature (in Kelvin). The given molar heat of vaporization of ethanol is 39.3 kJ/mol, and this should be converted to J/mol for the calculations, which becomes 39300 J/mol. The boiling point of ethanol is given as 78.3 degrees Celsius. If we want to convert this to Kelvin, we add 273.15, giving us 351.45 K. Now, substituting into the formula gives ΔS = 39300 J/mol / 351.45 K = 111.8 J/mol*K. So the change in entropy for the vaporization of ethanol is 111.8 J/mol*K.
Learn more about Entropy of Vaporization here:
https://brainly.com/question/34430500
#SPJ11
Thanks for taking the time to read The molar heat of vaporization of ethanol is 39 3 kJ mol and the boiling point of ethanol is 78 3 degrees Celsius Calculate the. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
