High School

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The population, [tex] p [/tex], of a town after [tex] t [/tex] years is represented using the equation [tex] p = 10000(1.04)^{-t} [/tex]. Which of the following is an equivalent expression?

A. [tex] p = 10000\left(\frac{1}{25}\right)^t [/tex]
B. [tex] p = 10000\left(\frac{25}{26}\right)^t [/tex]
C. [tex] p = 10000\left(\frac{26}{25}\right)^t [/tex]
D. [tex] p = 10000\left(\frac{25}{1}\right)^t [/tex]

Answer :

We start with the population equation:

[tex]$$
p = 10000\,(1.04)^{-t}.
$$[/tex]

Using the exponent property, a negative exponent can be rewritten as a reciprocal:

[tex]$$
p = 10000\left(\frac{1}{1.04}\right)^t.
$$[/tex]

Next, we express [tex]$\frac{1}{1.04}$[/tex] as a common fraction. Notice that:

[tex]$$
\frac{1}{1.04} = \frac{1}{\frac{26}{25}},
$$[/tex]

because [tex]$1.04 = \frac{26}{25}$[/tex]. Taking the reciprocal gives:

[tex]$$
\frac{1}{\frac{26}{25}} = \frac{25}{26}.
$$[/tex]

Substituting back into our equation, we have:

[tex]$$
p = 10000\left(\frac{25}{26}\right)^t.
$$[/tex]

Comparing this with the multiple-choice options, the equivalent expression is:

[tex]$$
10000\left(\frac{25}{26}\right)^t.
$$[/tex]

Thus, the correct answer is option 2.

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