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An inclined plane, which slopes at [tex]37^\circ[/tex], is used to raise a 10 kg object to a height of 4 m. If the efficiency of this machine is 80%, what is the amount of the load force?

A. 108 N
B. 100 N
C. 118 N
D. 98 N

Answer :

The load force An inclined plane, which slopes at 37 o, is used to raise a 10kg object to a height of 4m is 100 N.

How to find the load force

The formula for the efficiency of a machine is:

Efficiency = (Output Work)/(Input Work)

In this case, the output work is the work done by the load force to lift the object, and the input work is the work done by the effort force to push the object up the inclined plane.

The work done by the load force is:

Work = Force * Distance

Work = (Load Force) * (4 m)

The work done by the effort force is:

Work = Force * Distance

Work = (Effort Force) * (4 m * sin(37°))

The efficiency of the machine is 80%, so:

0.8 = (Load Force) / (Effort Force * 4 m * sin(37°))

0.8 * Effort Force * 4 m * sin(37°) = (Load Force)

Load Force = 0.8 * Effort Force * 4 m * sin(37°)

We know that the mass of the object is 10 kg, so the weight of the object is:

Weight = Mass * Gravity

Weight = 10 kg * 9.8 m/s²

Weight = 98 N

The force required to lift the object is equal to the weight of the object, so the effort force is 98 N.

Substituting this value into the equation for the load force, we get:

Load Force = 0.8 * 98 N * 4 m * sin(37°)

Load Force = 100 N

Therefore, the load force is 100 N.

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