High School

We appreciate your visit to What is the area of water that is open to the atmosphere in acres and square feet if the water surface elevation is uniformly 45. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

What is the area of water that is open to the atmosphere in acres and square feet if the water surface elevation is uniformly 45 feet above the reservoir bed and the reservoir is holding 10 billion gallons of water?

Answer :

The area of water that is open to the atmosphere in acres and square feet, if the water surface elevation is uniformly 45 ft above the reservoir bed and the reservoir is holding 10 billion gallons of water is 436.59 acres and 19,015,471.19 square feet.

The area of water that is open to the atmosphere in acres and square feet, if the water surface elevation is uniformly 45 ft above the reservoir bed and the reservoir is holding 10 billion gallons of water can be calculated as follows:Given data:The surface elevation of water from the reservoir bed is uniformly 45 feet.

The reservoir is holding 10 billion gallons of water.We know that the volume of a rectangular prism can be found by multiplying its length, width, and height. Here, we can consider the reservoir as a rectangular prism whose height is 45 ft. Let's assume that the length and width of the rectangular prism are 'l' and 'w,' respectively. Therefore, the volume of the rectangular prism can be expressed as:l x w x 45 cubic feetAlso, the volume of a rectangular prism can be calculated using the formula:Volume of a rectangular prism = length × width × height= 7.4805 gallons/cubic footHere, the volume of the rectangular prism is 10 billion gallons.

Therefore, we can say:Volume of rectangular prism = 10,000,000,000 gallons= l x w x 45 x 7.4805 cubic feet= 33,660.225 l x w cubic feetWe can also express the area of the water surface by dividing the volume by the height (45 ft).

Therefore:Area of the water surface = (10,000,000,000 gallons) / (7.4805 gallons/ cubic foot × 45 ft)= 19,015,471.19 square feet= 436.59 acres

Hence, the area of water that is open to the atmosphere in acres and square feet, if the water surface elevation is uniformly 45 ft above the reservoir bed and the reservoir is holding 10 billion gallons of water is 436.59 acres and 19,015,471.19 square feet.

Learn more about rectangular prism here,

https://brainly.com/question/24284033

#SPJ11

Thanks for taking the time to read What is the area of water that is open to the atmosphere in acres and square feet if the water surface elevation is uniformly 45. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada