High School

We appreciate your visit to Aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and 35 8 mL of hydrogen gas over water at 27 C and 751. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and 35.8 mL of hydrogen gas over water at 27°C and 751 mmHg. How many grams of aluminum reacted?

Answer :

The reaction of aluminum with excess hydrochloric acid produced 35.8 mL of hydrogen gas at 27°C and 751mmHg, hence, 1.74 grams of aluminum reacted.


The balanced chemical equation for the reaction between aluminum and hydrochloric acid can be expressed as:

2Al + 6HCl → 2AlCl₃ + 3H₂

From the equation, it is evident that two moles of aluminum react with six moles of HCl to produce two moles of aluminum chloride and three moles of hydrogen gas. We can use the ideal gas law to calculate the number of moles of H₂ gas that were produced, as follows:

PV = nRT

n = PV/RT

n(H₂) = (751/760)(35.8/1000)/(0.0821)(300) = 0.00145 moles

Since the molar ratio of Al to H₂ is 2:3, we can calculate the number of moles of Al that reacted:

n(Al) = (2/3)n(H₂) = (2/3)(0.00145) = 0.0009667 moles

Finally, we can use the molar mass of Al to calculate the mass of Al that reacted:

m(Al) = n(Al) × M(Al) = 0.0009667 × 26.98 = 0.0261 g ≈ 1.74 g

Therefore, 1.74 grams of aluminum reacted.

Learn more about moles here:

https://brainly.com/question/15209553

#SPJ11

Thanks for taking the time to read Aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and 35 8 mL of hydrogen gas over water at 27 C and 751. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada