High School

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At 2.00 s, the acceleration of a particle in counterclockwise circular motion is (6.00 m/s\(^2\), 4.00 m/s\(^2\)). The particle moves at a constant speed.

At what time does this occur?

A. 2.00 s
B. 4.00 s
C. 6.00 s
D. 8.00 s

Answer :

Final answer:

a) 2.00 s

The total acceleration of a particle in circular motion at t = 2.00 s is the sum of centripetal acceleration and tangential acceleration.

Explanation:

The total acceleration of the particle at t = 2.00 s is the sum of the centripetal acceleration and the tangential acceleration.

The centripetal acceleration is always directed towards the center of the circular path, while the tangential acceleration is perpendicular to the velocity of the particle.

By calculating the magnitudes of these accelerations at t = 2.00 s, we can determine the total acceleration experienced by the particle.

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