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Two cars leave towns 720 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 4 hours, what is the rate of the slower car?

Answer :

The rate of the slower car is calculated by using the formula for distance which is speed multiplied by time. This yields an equation which, when solved, gives the rate of the slower car as 71 km/hr.

The subject of this question is Mathematics, specifically, it's about rate, time, and distance problems in algebra. Both cars are moving towards each other from a total distance of 720km, and they meet after 4 hours. This translates to them covering the entire distance combined in that time period. We know that distance = speed × time. Since both cars meet after 4 hours, each car's distance covered is their respective speed × 4. Add these two equations together and they should equal to the total distance, i.e, 720km.

Let's denote the slower car's speed as x (in km/hr), then the faster car's speed will be x + 14 km/hr. Therefore, we can set up the equation: 4x (distance covered by slower car) + 4(x + 14) (distance covered by faster car) = 720. Solving this equation, we get x = 71. So, the speed of the slower car is 71 km/hr.


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