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A dust particle weighs [tex]$7.42 \times 10^{-10}$[/tex] kilograms. What is the weight of [tex]$5 \times 10^6$[/tex] dust particles represented in scientific notation?

A. [tex]3.71 \times 10^{-4}[/tex] kilograms
B. [tex]3.71 \times 10^{-3}[/tex] kilograms
C. [tex]37.1 \times 10^{-3}[/tex] kilograms
D. [tex]37.1 \times 10^{-4}[/tex] kilograms

Answer :

To find the weight of [tex]\(5 \times 10^6\)[/tex] dust particles, each weighing [tex]\(7.42 \times 10^{-10}\)[/tex] kilograms, you'll need to multiply the weight of one particle by the total number of particles. Here's a detailed explanation of how to perform this calculation:

1. Identify the weight of one particle:
The weight of one dust particle is [tex]\(7.42 \times 10^{-10}\)[/tex] kilograms.

2. Identify the number of particles:
There are [tex]\(5 \times 10^6\)[/tex] dust particles.

3. Calculate the total weight:
Multiply the weight of one particle by the number of particles:
[tex]\[
(7.42 \times 10^{-10}) \times (5 \times 10^6)
\][/tex]

4. Perform the multiplication of coefficients:
[tex]\(7.42 \times 5 = 37.1\)[/tex].

5. Perform the multiplication of powers of ten:
[tex]\(10^{-10} \times 10^6 = 10^{-4}\)[/tex].

6. Combine the results:
Multiply the results from steps 4 and 5:
[tex]\[
37.1 \times 10^{-4}
\][/tex]

7. Express the result in scientific notation:
The result [tex]\(37.1 \times 10^{-4}\)[/tex] is equivalent to [tex]\(3.71 \times 10^{-3}\)[/tex] when expressed in standard scientific notation by adjusting the decimal place.

So, the weight of [tex]\(5 \times 10^6\)[/tex] dust particles is [tex]\(3.71 \times 10^{-3}\)[/tex] kilograms. Therefore, the correct answer is:

B. [tex]\(3.71 \times 10^{-3}\)[/tex] kilograms.

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