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For as long as she can remember, Beth has had a lot of pet fish. She is in the market for a new fish tank shaped like a rectangular prism, which she wants to hold 75 gallons, or 17,325 cubic inches, of water. She wants the fish tank to be 48 inches long to fit perfectly along her wall, and she wants the tank to be twice as tall as it is wide. To the nearest tenth of an inch, how wide and tall should the tank be?

Answer :

The width of the tank should be approximately 5.71 inches, the height would be approximately is 11.42 inches.

How to calculate the ue dimensions

Given:

Length = 48 inches

Volume = 17,325 cubic inches

Substituting the values into the formula, we get:

17,325 = 96x³

Dividing both sides by 96:

x³ = 17,325 / 96

x³ ≈ 180.47

x ≈ ∛180.47

x ≈ 5.71

Therefore, the width of the tank should be approximately 5.71 inches. Since the height is twice the width, the height would be approximately 2 * 5.71 = 11.42 inches.

In conclusion, the height would be approximately is 11.42 inches.

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Rewritten by : Barada

Answer:

It was 13.4 inches wide and 26.9 inches tall