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A student at Hamden Middle School surveyed 20 seventh-grade students and obtained the following results regarding computer usage:

[tex]\[ 8, 15, 0, 11, 12, 13, 16, 13, 0, 4, 17, 14, 30, 13, 5, 12, 1, 13, 12, 21 \][/tex]

What is the ratio of the total number of students who used their computers to the total number of students surveyed?

A. [tex]\(\frac{2}{20}\)[/tex] or [tex]\(\frac{1}{10}\)[/tex]

B. [tex]\(\frac{2}{18}\)[/tex] or [tex]\(\frac{1}{9}\)[/tex]

C. [tex]\(\frac{18}{20}\)[/tex] or [tex]\(\frac{9}{10}\)[/tex]

D. [tex]\(\frac{18}{2}\)[/tex] or [tex]\(\frac{9}{1}\)[/tex]

Answer :

To solve this problem, we need to find the ratio of the total number of students who used their computers to the total number of students surveyed.

Here's how you can do it step-by-step:

1. List of Usage Data:
Look at the list of numbers given:
[tex]\[ 8, 15, 0, 11, 12, 13, 16, 13, 0, 4, 17, 14, 30, 13, 5, 12, 1, 13, 12, 21 \][/tex]
These numbers represent the amount of computer usage by each of the 20 students surveyed.

2. Count Total Students Surveyed:
We see that there are 20 numbers in the list. So, the total number of students surveyed is 20.

3. Count Students Who Used Computers:
Next, we need to determine how many students actually used their computers. This is done by counting how many numbers in the list are greater than 0. By checking through the list, you find there are 18 such numbers.

4. Calculate the Ratio:
The ratio is calculated as the number of students who used their computers (18) divided by the total number of students surveyed (20).

So, the ratio is:
[tex]\[
\frac{18}{20}
\][/tex]

5. Simplify the Ratio:
To simplify [tex]\(\frac{18}{20}\)[/tex], both the numerator and denominator can be divided by their greatest common divisor, which is 2:
[tex]\[
\frac{18 \div 2}{20 \div 2} = \frac{9}{10}
\][/tex]

Therefore, the ratio of students who used their computers to the total surveyed is [tex]\(\frac{9}{10}\)[/tex]. The correct choice from the options provided is [tex]\(\frac{18}{20}\)[/tex] or [tex]\(\frac{9}{10}\)[/tex].

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