Answer :

The force needed to bring the 1000 kg car to rest from a speed of 80.0 km/h in a distance of 115 m is approximately 2142.6 N.

To calculate the force needed to bring the car to rest, we can use the work-energy principle. The work done on the car is equal to the change in its kinetic energy.

The change in kinetic energy is given by:

ΔKE = (1/2) × m × (v² - u²)

Substituting the given values:

ΔKE = (1/2) × 1000 × (0² - 22.2²)

= -0.5 × 1000 × (-492.84)

= 246420 Joules

The work done to bring the car to rest is equal to the negative of the change in kinetic energy:

Work (W) = -ΔKE

= -246420 J

The work done is equal to the force applied multiplied by the distance traveled:

W = F × s

Rearranging the equation, we can solve for the force (F):

F = W / s

Substituting the known values:

F = -246420 J / 115 m

= -2142.6 N

The negative sign indicates that the force is in the opposite direction of motion, which is required to decelerate the car.

Therefore, the force needed to bring the 1000 kg car to rest from a speed of 80.0 km/h in a distance of 115 m is approximately 2142.6 N.

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