High School

We appreciate your visit to Marc attaches a falling 500 kg object with a rope through a pulley to a paddle wheel shaft He places the system in a well. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

Marc attaches a falling 500-kg object with a rope through a pulley to a paddle wheel shaft. He places the system in a well-insulated tank holding 25 kg of water. When the object falls, it causes the paddle wheel to rotate and churn the water.

If the object falls a vertical distance of 100 m at a constant speed, what is the temperature change of the water?

(Note: 1 kcal = 4,186 J, the specific heat of water is 4,186 J/kg·°C, and [tex]g = 9.8 \, \text{m/s}^2[/tex])

Answer :

Answer:

4.68227 °C

Explanation:

[tex]m_o[/tex] = Mass of object = 500 kg

[tex]m_w[/tex] = Mass of water = 25 kg

c = Specific heat of water at 20°C = 4186 J/kg°C

h = Height from which the object falls = 100 m

g = Acceleration due to gravity = 9.8 m/s²

The potential energy and heat will balance each other

[tex]PE=Q\\\Rightarrowmc m_ogh=m_oc\Delta T\\\Rightarrow \Delta T=\frac{m_ogh}{m_oc}\\\Rightarrow \Delta T=\frac{500\times 9.8\times 100}{25\times 4186}\\\Rightarrow \Delta=4.68227\ ^{\circ}C[/tex]

The temperature change in the water is 4.68227 °C

Thanks for taking the time to read Marc attaches a falling 500 kg object with a rope through a pulley to a paddle wheel shaft He places the system in a well. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada