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Answer :
Answer:
3.01 * 10 ^ 23 atoms of Pt
Explanation:
1 mole of Pt contains 6.02 * 10 ^ 23 atoms of Pt
195.084 g of Pt has 6.02 * 10 ^ 23 atoms of Pt
97.6 g = .5 moles so
97.6 g of Pt has 3.01 * 10 ^ 23 atoms of Pt
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Rewritten by : Barada
The 97.6 grams of platinum contains [tex]3.011\times 10^{23}[/tex] atoms.
Given:
The mass of platinum = 97.6 grams
To find:
The number of platinum atoms in 97.6 grams.
Solution:
Mass of platinum = 97.6 g
Moles of platinum =[tex]\frac{97.6g}{195.084 g/mol}=0.500 mol[/tex]
According to the mole concept:
1 mole = Avogadro Number = [tex]N_A=[/tex] [tex]6.022\times 10^{23} atoms/ molecules/ions[/tex]
The number of platinum atoms in 0.500 moles of platinum:
[tex]=0.500\times 6.022\times 10^{23} atoms\\\\=3.011\times 10^{23} atoms[/tex]
The 97.6 grams of platinum contains [tex]3.011\times 10^{23}[/tex] atoms.
Learn more about the mole concept here:
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